wyznacz x
daeva: (x+2) * [log3 3/7 + log3 21] = log4 4x−1
21 sty 19:02
Janek191:
| | 3 | |
( x + 2)*[ log3 |
| + log3 21] = log4 4 x −1 |
| | 7 | |
| | 3*21 | |
( x + 2)* log3 |
| = x − 1 |
| | 7 | |
( x + 2)* log
3 9 = x − 1
( x + 2)*2 = x − 1
2x + 4 = x − 1
2x − x = − 1 − 4
x = − 5
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21 sty 19:09
daeva: dzięki
21 sty 19:14