| x3−x2+x−1 | ||
b) lim ( | ) x→1 | |
| x3+x2−x−1 |
| 3√1+x − 3√1−x | ||
c) lim | x→0 | |
| x |
| √1+x +2 | ||
d) lim | x→∞ | |
| √1+x2 |
| √x − 103 | ||
e) lim | x→106 | |
| 3√x −102 |
| 1 | 2 | 3 | n | |||||
d) lim n√ | + | + | +... + | n→∞ | ||||
| 2 | 3 | 4 | n+1 |
| 1 | 1 | 1 | ||||
e) lim ( | + | + ... + | n→∞ | |||
| √n2+1 | √n2+2 | √n2+n |
| 3n+1 | ||
a) lim ( | )6n n→∞ | |
| 3n+2 |
| n | ||
b) lim ( | )n n→∞ | |
| n+1 |
| 1 | ||
c) lim ( 1+ | )3n−2 n→∞ | |
| n |
| n+4 | ||
d) lim ( | )5−2n n→∞ | |
| n+3 |
| (−1)n | ||
e) lim (1+ | ) (−1)nn n→∞ | |
| n |
no to szczerze współczuję konieczności
zaliczenia matematyki (aby miec możliwośc studiowania na 2 semestrze)