logarytmy aaagaaa: log₅ 20 * log² 5 + log² 2 jak to obliczyć?

utem:

log(20)
	*log2(5)+log2(2)=
log5

=log(20)*log(5)+log²(2)= =(log(4*5))*log(5)+log²(2)= =(log(4)+log(5))*log(5)+log²(2)= =2log(2)*log(5)+log²(5)+log²(2)=(log5+log2)²=log²(10)=1

aaagaaa: dzięki

utem: