.. patrick: Korzystając z definicji logarytmu, oblicz x, gdy: a) log₂(log₃x)=0 b) log₃[log₀,₅(x+1)]=1

pigor: ..., no to np. b) log₃[log_0,5(x+1)]=1 ⇔ log_0,5(x+1)=3¹ i x+1>0 i log_0,5(x+1)>0 ⇔ ⇔ x+1=0,5³ i x >−1 i x+1< 0,5⁰ ⇔ x=¹₈−1 i x>−1 i x< 0 ⇔ ⇔ x= −⁷₈ i −1< x< 0 ⇔ x∊{−⁷₈} . ...

Janek191: a) log₂ ( log₃ x ) = 0 ⇔ ( log₃ x = 2⁰ = 1 ∧ x > 0 )⇔ x = 3