Oblicz 8arcsin1-2arccos0+4(arctg1-arcctg(-1))
gladddiatus: Oblicz wartość wyrażenia: 8arcsin1−2arccos0+4(arctg1−arcctg(−1))
27 lis 19:56
Bogdan:
| | π | | π | |
arcsin1 = |
| bo sin |
| = 1 |
| | 2 | | 2 | |
| | π | | π | |
arccos0 = |
| bo cos |
| = 0 |
| | 2 | | 2 | |
| | π | | π | |
arctg1 = |
| bo tg |
| = 1 |
| | 4 | | 4 | |
arcctg(−1) = ... a teraz samodzielnie
27 lis 20:11
27 lis 20:15
Bogdan:
ok
27 lis 20:27