prosze pomocy pary: Oblicz Log o podstawie 1/3 z 27 Log o podstawie 27 z pierwiastek 3 Log o podstawie pierwiastek 3 z 27 Log o podsatwie 27 z 3 pierwiastek 3

dero2005: log_¹3 27 = x ⇔ (¹₃)^x = 27 (¹₃)^x = (¹₃)⁻³ x = −3

nieznajoma: A RESZTA DLAEJ NIE KUMAM

dero2005: log_a b = x ⇔ a^x = b log₂₇ √3 = x 27^x = √3 (3²)^x = 3^1₂ 3^2x = 3^1₂ 2x = ¹₂ x = ¹₄ załapałaś?

Janek191: log₂₇ √3 = x ⇔ 27^x = √3 ⇔ (3³)^x = 3^1₂ ⇔

	1		1
⇔ 33x = 312 ⇔ 3x =		⇔ x =
	2		6

Janek191: log_√3 27 = x ⇔ (√3)^x = 27 ⇔ ( 3^1₂)^x = 3³ ⇔

	x
⇔ 3x2 = 33 ⇔		= 3 ⇔ x = 6
	2

Janek191: log₂₇ 3√3 = x ⇔ 27^x = 3 √3 ⇔ (3³)^x = 3¹*3^1₂ ⇔

	3		1
⇔33x = 3112 ⇔ 3x =		⇔ x =
	2		2