sin3x Math: Cześć. Jak obliczyć wartości funkcji sin3x np. w punktach u{π} {3}, u{π} {2},π?

Math: ^π₆,^π₃,π

~r.: x=^π₆, x=^π₃,x=^π₂, x=π

~r.: tzn. sin(3*^π₆), sin(3*^π₃) itd.

Janek191:

	π
x =
	3

	π
sin 3*		= sin π = 0
	3

−−−−−−−−−−−−−−−−

	π
x =
	2

	π		3
sin 3*		= sin		π = − 1
	2		2

−−−−−−−−−−−−−−−−−−− x = π sin 3*π = sin (π +2π) = sin π = 0 −−−−−−−−−−−−−−−−−−−−−−−−−−−

	π
x =
	6

	π		π
sin 3*		= sin		= 1
	6		2

−−−−−−−−−−−−−−−−−−−