proszeo pomoc
asia: log3x +log5x= log15/log3
10 lis 23:49
asia: pomoze ktos?
10 lis 23:54
ICSP: x > 0 i mamy :
log
3 x + log
5 x = log15/log3
| log x | | log x | | log15 | |
| + |
| = |
| // * log 3 |
| log3 | | log5 | | log3 | |
| | log3 | |
logx(1 + |
| ) = log 15 |
| | log5 | |
| | log15 | |
logx ( |
| ) = log 15 |
| | log5 | |
logx = log 5
x = 5 ∊ D
f
11 lis 01:07