Oblicz logarytm Nie Uk: (log₂36*log₃36 ):( log₂36+log₃36 ) podpowiem że ma wyjść 2 ale jak do tego dojśc

dan: zgadza się będzie 2. log₂(36)*log₃(36) =−−−−−−−−−−−−−−−−−−−= log₂(36)+log₃(36) stosujemy zamianę podstaw logarytmu log₃(36 −−−−−−−−−−− * log₃(36) log₃(2) −−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−− = log₃36 −−−−−−−−−−−−−−−−−−−−+ log₃(36) log₃(2) sprowadzamy mianownik do wspólnego mianownika log₃(36) −−−−−−−−−−− * log₃(36) log₃(2) −−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−− = log₃(36) + log₃(2) * log₃(36) −−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−− log₃(2) skracamy wyrażenie log₃(2) i log₃(36) otrzymujemy log₃(36) −−−−−−−−−−−−−−−−−−−−− = 1+log₃(2) log₃(36) =−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−− = log₃(3) +log₃(2) log₃(36) =−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−− = log₃(6) 2log₃(6) =−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−− = 2 log₃(6)

dan: niech ktoś sprawdzi ?

AROB: Ok.