logarytmy aaa: log₂ 7−log₂ 63+log_√2 36

Janek191:

	7
log2 7 − log2 63 + log√2 36 = log2		+ log√2 36 =
	63

	1		1
= log2		+ log20,5 36 = log2		+ 2 log2 36 =
	9		9

	1		1
= log2		+ log2 362 = log2 (		*36*36} =
	9		9

= log₂ (4*4*9) = log₂ (16*9) = log₂ 16 + log₂ 9 = log₂ 2⁴ + log₂ 3² = = 4 log₂ 2+ 2 log₂ 3 = 4*1 + 2 log₂ 3 = 4 + 2 log₂ 3 ===============================================

	1
log aα x =		loga x
	α

Gustlik: Lepiej wzorem na zmianę podstawy logarytmu:

	7		log236
log2 7−log2 63+log√2 36=log2		+		=
	63		log2√2

	1		log236		1
=log2		+		=log2		+2log236=
	9		12		9

	1		1
=log2		+log2362=log2		+log21296=
	9		9

	1
=log2(		*1296)=log2144=log2(24*32)=
	9

=log₂2⁴+log₂3²=4+2log₂3 144 | 2 72 | 2 36 | 2 18 | 2 9 | 3 3 | 3 1 |