| 3 | 1 | 1 | ||||
...........= (6+2√9−5)−1 *( | −1)= 10* | = | ||||
| 2 | 2 | 20 |
| 1 | 1 | |||
a−2= | . | |||
| a2 | (3−√5)1/2+(3+√5)1/2)2 |
| 1 | ||
(a+b)2=a2+2ab+b2. | ||
| 3−√5+2(3−√5)1/2(3+√5)1/2+3+√5 |
| 1 | 1 | 1 | ||||
(a−b)(a+b)=a2−b2. | = | = | ||||
| 6+2*√9−5 | 6+2*2 | 10 |
| 27 | 3√27 | 3 | |||
1/3= | = | ||||
| 8 | 3√8 | 2 |
| 1 | 3 | 1 | 1 | 1 | |||||
*( | −1)= | * | = | ||||||
| 10 | 2 | 10 | 2 | 20 |
1/ podnieść do kwadratu
2/ zastosować odwrotność
