| π | √2 | |||
Pomógłby ktoś w rozwiązaniu takiej nierówności −−−> |sin(x − | )| < | |||
| 3 | 2 |
y=sinx
| √2 | ||
y= | ||
| 2 |
| √2 | ||
y= | ||
| 2 |
| π | π | |||
(1) 0+2kπ < (x− | )< | +2kπ | ||
| 3 | 4 |
| 3π | π | 5π | ||||
(2) lub | +2kπ < (x− | )< | +2kπ | |||
| 4 | 3 | 4 |
| 7π | π | |||
(3) lub | +2kπ < (x− | )<2π+2kπ | ||
| 4 | 3 |
| π | 7 | |||
(1) | +2kπ<x< | π+2kπ | ||
| 3 | 12 |