wyznacz x

wyznacz x blackmagic: 2^x+2^x−1+3*2^x−2=18

25 sie 18:29

Janek191: 2^x + 2^{x −1} + 3*2^{x − 2} = 18 2^x−2 *{ 2² + 2 + 3] = 18 2^{x −2} *9 = 18 / : 9 2^{x −2} = 2 x − 2 = 1 x = 3 =====

25 sie 18:42