Wielomiany Małgi: Rozwiąż: a) 24x³ − 10x² − 3x + 1 = 0 b) (8 − 5x)(x + 3)³(x + 2)² ≤0 c) (2 − 3x)(9 − x²)²(x² − x − 12)>0

pigor: ..., np. a) 24x³−10x²−3x+1= 0 ⇔ 24x³−12x²+2x²−x−2x+1= 0 ⇔ ⇔ 12x²(2x−1)+x(2x−1)−1(2x−1)=0 ⇔ (2x−1) (12x²+x−1)= 0 ⇔ ⇔ 2(x−¹₂) (12x²−3x+4x−1)= 0 ⇔ 2(x−¹₂) [3x(4x−1)+1(4x−1)]= 0 ⇔ ⇔ 2(x−¹₂) (4x−1) (3x+1)= 0 ⇔ 2*4*3 (x−¹₂) (x−¹₄) (x+¹₃)= 0 ⇔ ⇔ x= ¹₂ lub x= ¹₄ lub x= −¹₃ ⇔ x∊ {¹₂, ¹₄,−¹₃} . ...