Wiedząc, że log12 = a i log2 = b, oblicz log90.
domisimply: Wiedząc, że log12 = a i log2 = b, oblicz log90.
8 cze 18:34
Basia:
log90 = log(9*10) = log9 + log10 = 1 + log3
2 = 1+2log3 =
| | 12 | |
1 + 2log |
| = 1+2(log12 − log4) = |
| | 4 | |
1+2(a − log2
2) = 1+2(a−2log2) = 1+2(a−2b) = 2a−4b+1
8 cze 18:42
Eta:
log12= log4+log3= 2log2+log3 = 2b+log3 =a ⇒ log3= a−2b
log90= log9+log10= 2log3+1 = .......... dokończ
8 cze 18:44
Eta:
8 cze 18:45