| 1 | ||
b) ...= | −4=... dokończ
| |
| 4 |
−1+6+1+1=7
3. dobrze
2.
√12=2√3
| 6+2√3 | 3+√3 | |||
x1= | = | |||
| 4 | 2 |
| 3−√3 | ||
x2= | ||
| 2 |
| −7−√69 | 7+√69 | |||
x1= | = | |||
| −2 | 2 |
| −7+√69 | 7+√69 | |||
x2= | = | |||
| −2 | 2 |
c) w zaspisie w trzeciej linijce brakuje ci kwadratu nad x.
| 6−√12 | 6+√12 | |||
x∊( −∞, | > U < | ,∞) | ||
| 4 | 4 |


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