pigor: ..., albo jeśli było tam +2m
2, a reszta bez zmian, to
m3+2m2−3m−6= m
2(m+2)−3(m+2)= (m+2)(m
2−3)=
(m+2)(m−√3)(m+√3)
−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−
..., albo jeśli było tam +3m, a reszta bez zmian, to
m3−2m2+3m−6= m
2(m−2)+3(m−2)=
(m−2)(m2+3) . ...