rownania wykladnicze... pomocy :(
Dajana: (2/5)x2−1 * (25/4)−2x=(√2/5)4x−4x2
10 mar 21:58
Beti: | | 2 | | 2 | | 2 | |
( |
| )x2−1 * ( |
| )−2*(−2x) = ( |
| )(1/2)*(4x−4x2) |
| | 5 | | 5 | | 5 | |
| | 2 | | 2 | |
( |
| )x2−1+4x = ( |
| )2x−2x2 |
| | 5 | | 5 | |
↓
x
2−1+4x = 2x−2x
2
rozwiąż teraz równ. kradratowe
10 mar 22:08
Dajana: Ogromne dzieki za pomoc
10 mar 22:10