Z podobieństwa trójkątów:
| a | h | ahb | ||||
ABD i ESD mamy proporcję: | = | ⇒ e = | , | |||
| e | hb | h |
| a | h | ahb | ||||
ABC i FSC mamy proporcję: | = | ⇒ f = | ||||
| f | hb | h |
| 1 | 1 | |||
PASD = | eh oraz PBSC = | fh, skoro e = f, to PASD = PBSC. | ||
| 2 | 2 |
| 1 | 1 | |||
PABD = | ah oraz PABC = | ah. | ||
| 2 | 2 |
| 1 | 1 | |||
PACD = | bh oraz PBCD = | bh. | ||
| 2 | 2 |