| 4 | ||
Kąt α jest ostry i tg α = | . Oblicz sin α + cosα | |
| 3 |
| tg(x) | ||
sin(x) = | ||
| √1 + tg2(x) |
| 1 | ||
cos(x) = | ||
| √1 + tg2(x) |
| 4 | ||
Ale to nie potrafisz do wzoru wstawić zamiast tg(x) = | ? | |
| 3 |
| 4 | 3 | |||
sinα= | a cosα= | tak? | ||
| 5 | 5 |
| 4 | 3 | |||
tg(x) jest > 1 to sin(x) > cos(x) tak więc sin(x) = | i cos(x) = | . | ||
| 5 | 5 |