matematykaszkolna.pl
logarytmy Pati: Oblicz, wiedząc, że: expa (x) = a x a) exp2 (log2 5)= b) exp2 (log4 9)
7 cze 17:25
Basia: logab=c ⇔ ac=b alogab=ac=b alogab=b exp2(log25)=2log25=5 −−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−
 logcb 
logab=

 logca 
 log29 log29 
log49=

=

 log24 2 
exp2(log49)=2log49=2log292 = (2log29)12 = 912=9=3
7 cze 17:35