zlozenia funkcji buum: znalezc zlozenia funkcji f(x) = 1−x g(x)= x² f(x) = e^x g(x) = ln x f(x) = sin x , x∊<−π,π> g(x) = arcsinx

	⎧	0
f(x) =	⎩	x	x∊(−∞,0) i x ∊( 0,∞) g(x) = k{0&−x2} x∊( −∞,0) i x∊(0,∞)

Janek191: 1) f(x) = 1 − x g(x) = x² więc ( f o g) (x) = f( g(x)) = f(x²) = 1 − x² (g o f)(x) = g( f(x)) = g( 1 − x) = (1 − x)² −−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−