oblicz mietek :

2 log3 4 − 3 log3 12)
3 + log3 4

nie wiem jak zrobić to 3 + log₃ 4

edi: Licznik = 2log₃4− 3(log₃3+log₃4)= 2log₃4−3−3log₃4= −(3+log₃4)

−(3+log34)
	= −1
3+log34

mietek :

log3 (42 : 123)
3 + log3 4

mietek : dzięki

Janek 191: log3 (4² : 12³) = log3 ( 4² : ( 3*4)³) = log 3 (1/(27*4) ) = log3 [ (1/27)*(1/4)) = = log3(1/27) + log3 (1/4) = − 3 + log 3 [ 4⁻¹] = − 3 − log 3 4 zatem log 3 [ 4² : 12³] −−−−−−−−−−−−−−−−−−−−−−− = − 1 3 + log3 4

asdf:

1   log3( )   108		log3(1/108)		log3(1/108)
	=		=		=
3 + log34		log3 27*4		log3108

log3(108)−1		log...
	= −		= − 1
log3108		log...