aaa
aaa: wiadomo ze a=x+1x−1 zatem
A. x=1+a
B. x=a−1a+1
C. x=a+1a−1
D. x=1
27 gru 18:55
ICSP: | | x+1 | | x−1+2 | | 2 | |
a = |
| = |
| = 1 + |
| |
| | x−1 | | x−1 | | x−1 | |
27 gru 18:57
pigor: ... lub
a=
x+1 x−1 /*(x−1) i x≠1 ⇔ ax−a= x+1 ⇔ ax−x= a+1 ⇔
⇔ x(a−1}= a+1 ⇔
x= a+1 a−1 i a≠1 , czyli odp.
C.. ...
27 gru 20:05