trygonometria stryq: 2arcsin(− ¹₂) + arctg(tg ⁷₈ π) − arctg1 no to tak 2arcsin(− ¹₂) = − ^π₃ arctg1 = ^π₄ jak ogliczyc arctg(tg ⁷₈ π) ?

stryq: pomoze ktos ? bo jestem pod sciana

stryq: podbijam..

Mila:

	π
arcsin(−1/2)=−arcsin(1/2)−
	6

y=arctgx ; x∊R ; y∊(−π/2;π/2)

7π		π
	>
8		2

	7π		π		π
tg		=tg(π−		)=−tg
	8		8		8

	7π		π		π		π
arctg(tg(		))=arctg(−tg(		))=−arctg(tg		)=−
	8		8		8		8