sinus
Monika: sin3x+sin5x=0
26 lis 22:38
Aga1.: | | x+y | | x−y | |
Zastosuj wzór sinx+siny=2sin |
| *cos |
| |
| | 2 | | 2 | |
26 lis 22:41
Monika: 2sin4x*(−cosx)=0
26 lis 22:43
inka:
sin5x = sin(−3x)
5x = −3x + 2kπ lub 5x = π + 3x + 2kπ
8x = 2kπ lub 2x = π + 2kπ
| | kπ | | π | |
x = |
| lub x = |
| + kπ |
| | 4 | | 2 | |
26 lis 22:44