| log3x | ||
log√27x3 = 3log√27x = 3* | = | |
| log3√27 |
| log3x | ||
3* | = .... | |
| log3(33)1/2 |
| 15 | ||
log153 = log15 | = log15{15} − log155 = 1−log155 | |
| 5 |
Dzięki jeszcze raz,bardzo mi pomogłaś !
| 1 | ||
log155√3 = log155+log31/2 = log155 + | log153 = | |
| 2 |
| 1 | a+1 | |||
a + | *(1−a) = | |||
| 2 | 2 |
Mam jeszcze jeden problem.
http://vlep.pl/eydflh.png