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	x		x2+8		1		x2		2
(		+		−		)*(		−		)
	x2+2x+4		x3−8		x−2		x2−4		2−x

M:

Bo_ra: Założenia x²+2x+4≠0 x∊ℛ x³−8≠0 (x−2)(x²+2x+4)≠0 x≠2 x−2≠0 x≠2 x²−4≠0 (x−2)(x+2)≠0 x≠−2 x≠2 2−x≠0 x≠2 D=ℛ\{−2,2}

	x		x2+8		1		x2		2
(		−		−		) *(		+		)=
	x2+2x+4		x3−8		x−2		x2−4		x−2

	x(x−2)+x2+8−1(x2+2x+4)		x2+2(x+2)
=		*		=
	(x−2)(x2+2x+4)		x−2)(x+2)

	x2−2x+x2+8−x2−2x−4		x2+2x+4
=		*		=
	(x−2)(x2+2x+4)		(x−2)(x+2)

	x2−4x+4		x2+2x+4
=		*		=
	(x−2)(x2+2x+4)		(x−2)(x+2)

	(x−2)2		x2+2x+4
=		*		=
	(x−2)(x2+2x+4)		(x−2)(x+2)

	1
=
	x+2