Pomocy Kurde: In an effort to better understand the behavior of atomic systems, the Danish physicist Niels Bohr (1885−1962) introduced a simple model for the hydrogen atom. In the Bohr model, at is known today, the electron is imagined to move in a circular orbit about a stationary proton. The force responsible for the electron’s circular motion is the electric force of attraction between the electron and the proton. Given that the radius of the electron’s orbit is 5.29*10⁻¹¹m, and its mass is me = 9.11*10⁻³¹kg, find the electron’s speed.

Saizou : i co w tym niezrozumiałego?

cho:

	v2		qe * qp
F = ma ⇒ F = m		, ponadto F = k *
	r		r2

	v2		qe * qp
m		= k *
	r		r2

	qe * qp
mv2 = k *
	r

	qe * qp
v2 = k *
	r * m

	qe * qp
v = (k *		)1/2
	r * m

Trivial: r = 5.29·10⁻¹¹ [m] m_e = 9.11·10⁻³¹ [kg]

	1		e2
Fe =		·		.
	4πε0		r2

Pomijając efekty relatywistyczne mamy:

	v2		1		e2
Fe = meac = me		=		·
	r		4πε0		r2

	e		m
v =		= 2.185·106 [		]
	2√πε0mer		s

Trivial: Ah, widzę, że ktoś mnie wyprzedził.