granica
michał: Oblicz granice funkcji:
lim √4n+2n−√4n−2n
n−>∞
17 cze 17:51
michał: lim √4n+2n−√4n−1
n−>∞
17 cze 17:53
michał: to własciwe:
lim √4n+2n −√4n+1
n−>∞
17 cze 17:54
Artur z miasta Neptuna:
to się zdecyduj jak jest w końcu
| | √4n+2n−√4n−1 | | √4n+2n+√4n−1 | |
√4n+2n−√4n−1= |
| * |
| = |
| | 1 | | √4n+2n+√4n−1 | |
| | 4n + 2n − (4n−1) | | 2n + 1 | | 1 | |
= |
| = |
| −> |
| |
| | √4n+2n + √4n−1 | | √4n+2n + √4n−1 | | 2 | |
17 cze 18:17