dowodzik
Mat: Punkt O lezy wewnatrz rownolegoboku ABCD. Wykaz ze suma pol trojkatow: AOB i COD jest rowna
sumie pol trojkatow AOD i COB
6 cze 11:52
Artur_z_miasta_Neptuna:
| | a*h1 | | a*h3 | | a*(h1+h3) | | a*H | | 1 | |
PΔ1 + PΔ3 = |
| + |
| = |
| = |
| = |
| *PABCD |
| | 2 | | 2 | | 2 | | 2 | | 2 | |
| | b*h2 | | b*h4 | | b*(h2+h4) | | b*H' | | 1 | |
PΔ2 + PΔ4 = |
| + |
| = |
| = |
| = |
| *PABCD |
| | 2 | | 2 | | 2 | | 2 | | 2 | |
c.n.w.
6 cze 12:09