| √2 | ||
a) cosx = − | ||
| 2 |
| π | π | 3π | ||||
cosx = −cos | => cosx = cos(π − | ) => cosx = cos | ||||
| 4 | 4 | 4 |
| 3π | 3π | |||
x = | + k*2π lub x = − | + k*2π, k € C | ||
| 4 | 4 |
| √3 | π | |||
= sin | ||||
| 2 | 3 |
| π | ||
c) Podpowiedź: 1 = ctg | , potrzebny jest wykres y = ctgx i wykres y = 1 | |
| 4 |