|x-10|*log_2(x-3)=2x-20 zad: |x−10|*log₂(x−3)=2x−20

M:

Mila: D=(3,∞) 1) x∊(3,10) −(x−10)log₂(x−3)−2(x−10)=0 (x−10)(−log₂(x−3)−2)=0 log₂(x−3)=−2 x−3=2⁻²

	1
x=3
	4

2) x≥10 (x−10)log₂(x−3)−2(x−10)=0 (x−10)*(log₂(x−3)−2)=0 x=10 lub log₂(x−3)=2 x−3=2² x=7∉D =====

	13
x=10 lub x=
	4