| 2 | |
< m Z: x ≠ 0 ∧ m ≠ 0 | |
| x |
| 3 | ||
x∊(− | , 0) | |
| 2 |
| 2 | mx | ||
< | |||
| x | x |
| 2 | mx | ||
− | < 0 | ||
| x | x |
| 2 − mx | |
< 0 | |
| x |
| 2 | ||
x = 0 ∨ x = | ||
| m |
| 3 | ||
x = 0 ⇔ zgadza się, pozostanie przyrównać do x = − | ||
| 2 |
| 3 | 2 | 3 | 4 | |||||
x = − | ⇔ | = − | ⇔ m = − | |||||
| 2 | m | 2 | 3 |
| 4 | ||
x(2 + | x) < 0 | |
| 3 |
| 4 | 3 | ||
x(x + | ) < 0 | ||
| 3 | 2 |