Może może może ktoś sprawdzić?
| 4√3 | |
−2√3= | |
| √3−1 |
| 4√3 | √3+1 | |||
= | * | −2√3= | ||
| √3−1 | √3+1 |
| 12+4√3 | ||
= | −2√3=6+2√3−2√3=6 | |
| 2 |
Dziękuje MILA
Wesołych świąt!
| 4√3 | 4√3−(1+2√3)(√3−1) | ||
−1−2√3= | =
| ||
| √3−1 | √3−1 |
| 4√3−√3+1−6+2√3 | 5√3−5 | (5√3−5)(√3+1) | ||||
= | = | = | =
| |||
| √3−1 | √3−1 | 2 |
| 15−5 | |
=5 | |
| 2 |