kąt rozwarcia stozka
lalala: Oblicz kąt rozwarcia stożka jeśli pole podstawy jest równe 9π a jego objetosc wynosi 3√3π.
27 mar 15:15
asdf:

Pp = πr
2 ⇒ r = 3 (założenie r > 0)
−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−
V = 3
√3π
| 1 | |
| * 9π * H = 3√3π || * 3 |
| 3 | |
9π * H = 9
√3 π
H =
√3
−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−
| | 3 | |
tgα = |
| ⇒ tgα = √3 ⇒ 60o |
| | √3 | |
Kąt rozwarcia to 120o
27 mar 15:30