logarytmy
Iza19: Wiadomo, że log5 11 = a . Wykaż, że log121 5√5 = 34a
26 mar 19:06
Iza19: ten drugi logarytm wynosi 121 z 5√5 a nie 1* 21 5√5
26 mar 19:08
pigor: ... np. tak :
| | log55*512 | | log5532 | |
log1215√5 = |
| = |
| = |
| | log5121 | | log5112 | |
| | 32log55 | | 32 | | 3 | |
= |
| = |
| = |
| c.n.w. . ...  |
| | 2log511 | | 2a | | 4a | |
26 mar 19:13