trygonometria
Aguś: kąt α jest ostry i sinαcosα= 0,22. Oblicz sinα+cosα. Pliska pomóżcie
7 mar 20:56
Artur z miasta Neptuna:
zał. α<90
o ⇔ sinα + cosα > 0
| | 122 | |
(sin α + cos α)2 = sin2α + 2sinαcosα + cos2α = 1 + 0.22 = |
| |
| | 100 | |
| | √122 | | √122 | |
⇔ sin α + cos α = |
| = |
| |
| | √100 | | 10 | |
7 mar 21:31
Artur z miasta Neptuna:
tfu ...
| | 144 | | 12 | | 6 | |
(sin α + cos α)2 = 1 + 0.44 = |
| ⇔ sin α + cos α = |
| = |
| |
| | 100 | | 10 | | 5 | |
7 mar 21:32