proszę o pomoc ewelinka918273: Rozwiąż równanie: √7^x * √3^x=5

Eta: √7^x*√3^x= 7^x/2*3^x/2= 21^x/2

	x
i mamy: 21x/2=5 ⇒		= log215 ⇒x=2log215= log2125
	2

testy-zadania: sqrt(7)^x sqrt(3)^x = 5 21⁽x/2) = 5 sqrt(21^x) = 5 x = (2 log(5))/(log(3)+log(7)) x~~1.0572678936388961293 x = (2 (log(5)+2 i pi n))/(log(3)+log(7)), n element Z x~~0.65691747750610214668 (6.2831853071795864769 i n+1.6094379124341003746), n element Z