matematykaszkolna.pl
oblicz całke dori: ∫x3(2−x4)8dx
14 sty 15:16
gwiazda: t=2−x4 dt=−4x3 dx/−4 −14dt=x3 dx ∫−14 t8dt
14 sty 15:18
student: ...=| t=2−x4 | = −1/4 ∫t8dt= −1/4 * 1/9*t9 +C= =1/36*(2−x4)9+C | dt = −4x3dx | | −dt/4=x3dx |
14 sty 15:22