oblicz Jan: log₅(3x−11)+log₅(x−27)=3+log₅ 8 Pilne a mi wychodzą bzdury!

aa: D: 3x−11>0 x−27>0 x>¹¹₃ x>27 x∊(27, +∞) log₅[(3x−11)(x−27)]=log₅5³+log₅8 log₅(3x²−81x−11x+297)=log₅(125*8) 3x²−92x+297=1000 3x²−92x−703=0 Δ−8464−4*3*(−703)=16900 √Δ=130

	92−130		38
x1=		=−		∉D
	6		6

	222
x2=
	6

szaaatan: 648β + 698Ω = 74165∑