zesp
united: Witam. Jak obliczyć x3+27=0 jeśli chodzi o l. zespolone?
22 lis 17:57
united: pomoże ktoś?
22 lis 19:11
:): (x+3)(x
2−3x+9)=0
x+3=0 x=−3
x
2−3x+9=0
| | 3 | | √27 | | 3 | | √27 | |
(x− |
| −i |
| )(x− |
| +i |
| )=0
|
| | 2 | | 2 | | 2 | | 2 | |
| | 3 | | 3√3 | | 3 | | 3√3 | |
x= |
| +i |
| lub x= |
| −i |
| |
| | 2 | | 2 | | 2 | | 2 | |
22 lis 19:35
united: dzięki
22 lis 19:52