:) Grześ: Takie tam zadanko...

	4x−9x−1		x−4+3x−1
b) (		+		)2=
	2x1/2−3x−1/2		x1/2−x−1/2

	x−1(4x2−9)		x−1(x2−4x+3)
=(		+		)2=
	x−1/2(2x−3)		x−1/2(x−1)

	x−1(2x−3)(2x+3)		x−1(x−1)(x−3)
=(		+		)2, skracamy:
	x−1/2(2x−3)		x−1/2(x−1)

(x^−1/2(2x+3)+x^−1/2(x−3))²= =(x^−1/2)² * (2x+3+x−3)²=x⁻¹ * (3x)²=x⁻¹ * 9x² =9x

	x3√y		√x
c) ((		)3/2 + (		)2) : (x1/4+y1/4) =
	y√x3		x8√y3

= ((x^−1/2y^−2/3)^3/2 + (x^−1/2y^−3/8)²) : (x^1/4+y^1/4) = =(x^−3/4y⁻¹+x⁻¹y^−3/4) : (x^1/4+y^1/4) = =x⁻¹y⁻¹(x^1/4 + y^1/4) : (x^1/4+y^1/4) =

	1
=x−1y−1=
	xy

ziomek: aha