Oblicz granice ciągu
Damian: x4−3x+2
lim −−−−−−−−−−−−− =
x−>1 x5−4x+3
22 sie 21:25
Eta:
= 1
22 sie 21:32
Eta:
| | (x−1)(x3+x2+x−2) | | x3+x2+x−2 | |
lim |
| =lim |
| = |
| | (x−1)(x4+x3+x2+x−3) | | x4+x3+x2+x−3 | |
x→ 1
=f(1)=...........
22 sie 21:38
Eta:
lub z de Hospitala
| | L' | | 4x−3 | | 4−3 | |
lim |
| = lim |
| = |
| =1 |
| | M' | | 5x−4 | | 5−4 | |
x→ 1
22 sie 21:42